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  7. Pressure Rise Through Impeller of Centrifugal Pump - Derivation & Equations

Pressure Rise Through Impeller of Centrifugal Pump - Derivation & Equations

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Learn how to calculate the pressure rise through an impeller of a centrifugal pump by deriving equations using Bernoulli's equations at the inlet and outlet of the impeller. Understand the process and principles of pressure increase through the impeller.
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Video Transcript

0:00
Hi, Professor Vishal Taylor, welcome to my YouTube channel.
0:04
In this video, I teach you the derivation of pressure rise through impeller of centrifugal
0:10
pump.
0:12
Means, how amount of the pressure is increased by an impeller of a centrifugal pump.
0:18
So in this case, we are deriving the equations by applying the Bernoulli's equations at the
0:25
inlet and outlet of the impellers.
0:26
So, this equation is correct.
1:00
Bernoulli's equations we are required a two section that is a section 1 and
1:05
section 2 so we are giving the section 1 at the inlet of this impeller okay this
1:10
is our center of the impeller from where the water is coming from suction pipe
1:15
then water is displaced this distance this is the inlet of impeller this is
1:20
the impeller van and at the outlet we give the section 2 okay so this is a two
1:25
sections where we applying the Bernoulli's equations so at the inlet of
1:30
is impeller that is
2:00
the water or increase the pressure of the water means the pressure is increased at the
2:04
section 2 that is a P2 pressure and inlet of the pump that is a P1 pressure.
2:08
So in this case we are finding the P2 minus P1 because it is a pressure rise so we are
2:14
find out the P2 upon P1.
2:16
So what is the energy at the input so water have 8 three types of energy kinetic energy
2:22
potential energy as well as the pressure energy that we all know.
2:26
So what is the equations at the inlet.
2:27
So inlet pressure is
3:00
equal to work output. So, at the output only hydraulic energy means at the outlet water
3:05
and water contain the hydraulic energy. So, water have three forms pressure energy, velocity
3:09
energy and potential energy. So, at the section 2, so pressure is P2. So, pressure head is
3:15
P2 upon rho g plus velocity V2. So, velocity head is V2 square upon 2g plus potential energy
3:23
that is Z2. So, this is the basic equation from that we derive this equation.
4:00
So, we writing this equation in the form of p2 minus p1 upon rho g.
4:05
So, p2 minus p1 because p2 is higher and p1 is smaller.
4:09
So, this p1 upon rho g is supply on the right side and the right side another parameter
4:14
is going on to this left side.
4:16
So, this equation is written like this way p2 minus p1 upon rho g.
4:21
And another parameter is V1 square upon 2g plus Vw2 into U2 upon g and this V2 square
5:00
equations, we put the value of V2 and Vw2 from these velocity triangles.
5:08
Before that, I request to like the video, subscribe the channel by pressing the subscribe
5:13
button and also press the bell icon to get continuous notifications.
5:20
So here I mentioned, from the outlet velocity triangle, we have tried to find out the value
5:26
of Vw2 and V2.
6:00
opposite sides upon adjacent side. Opposite side is Vf2 this one and adjacent side is
6:07
the U2 minus Vw2. So, this equation is written. Then after from this equation is further simplified
6:15
and we write down the equation of Vw2. So, Vw2 is equal to U2 minus Vf2 into cot beta
6:24
2 means this step is going on the left side and tan beta 2 is coming in the right side.
6:29
So, it is a one way.
7:00
of hypotenuse is equal to square of both the side. So, it is V2 square is equal to both
7:07
the side means Vw2 is one side and another side is the Vf2. So, this is Pythagoras equation.
7:14
Now in this equation, we are applying or putting this value of Vw2. What is the Vw2? That we
7:20
already derived the Vw2 is equal to u2 minus Vf2 cot beta 2. So, this is the equation of
7:27
V2. And it is further simplified below.
8:00
minus 2 into first step u2 into second step vf2 cot beta2.
8:05
So, this distribution takes place then remaining is the vf2 square.

Video Summary & Chapters

No chapters for this video generated yet.

Video Transcript

0:00
Hi, Professor Vishal Taylor, welcome to my YouTube channel.
0:04
In this video, I teach you the derivation of pressure rise through impeller of centrifugal
0:10
pump.
0:12
Means, how amount of the pressure is increased by an impeller of a centrifugal pump.
0:18
So in this case, we are deriving the equations by applying the Bernoulli's equations at the
0:25
inlet and outlet of the impellers.
0:26
So, this equation is totally derived by using this velocity diagrams of a centrifugal pump.
0:35
So for that, you at least know the how to draw velocity diagrams.
0:40
And if you don't know how to draw the velocity diagrams for a centrifugal pump, then I request
0:45
you to watch my video on a velocity diagram and work done of a centrifugal pump from the
0:51
playlist.
0:51
The link is also available in the description and also from the top right screen of your
0:56
mobile from the iSymbols.
0:58
Now, for applying the...
1:00
Bernoulli's equations we are required a two section that is a section 1 and
1:05
section 2 so we are giving the section 1 at the inlet of this impeller okay this
1:10
is our center of the impeller from where the water is coming from suction pipe
1:15
then water is displaced this distance this is the inlet of impeller this is
1:20
the impeller van and at the outlet we give the section 2 okay so this is a two
1:25
sections where we applying the Bernoulli's equations so at the inlet of
1:30
this impeller there are two things available. First one is the energy in the water at the
1:35
section 1 plus work done supplied by the impeller. And at the outlet there is only one thing
1:41
that is the water available at the section 2 means energy at the section 2. So, we are
1:46
writing that energy at the input plus work input by this impeller is equal to total work
1:52
output. This work output is in the form of water. So, we generally know the pump is used
2:00
the water or increase the pressure of the water means the pressure is increased at the
2:04
section 2 that is a P2 pressure and inlet of the pump that is a P1 pressure.
2:08
So in this case we are finding the P2 minus P1 because it is a pressure rise.
2:13
So we are find out the P2 upon P1.
2:16
So what is the energy at the input?
2:18
So water have 8 three types of energy kinetic energy, potential energy as well as the pressure
2:24
energy that we all know.
2:25
Okay, so what is the equations at the inlet?
2:27
So, inlet pressure is P1 upon rho g is known as the pressure energy plus velocity energy
2:33
velocity at the section 1 is the V1.
2:35
So, velocity energy is V1 square by 2g and the potential energy it is a Z1.
2:42
Plus work input by the impeller that is a work input by the impeller is the Vw2 into
2:47
U2 by g.
2:49
So, that we already discussed in a work done of centrifugal pump.
2:52
So, you can watch the Wordmem by Pom from the description or playlist for all the i
2:59
symbols.
3:00
Easy.
3:00
equal to work output. So, at the output only hydraulic energy means at the outlet water
3:05
and water contain the hydraulic energy. So, water have three forms pressure energy, velocity
3:09
energy and potential energy. So, at the section 2, so pressure is P2. So, pressure head is
3:15
P2 upon rho g plus velocity V2. So, velocity head is V2 square upon 2g plus potential energy
3:23
that is Z2. So, this is the basic equation from that we derive this equation.
3:28
Now, we consider that or we assume that z1 and z2 are equal because this impeller width
3:35
is negligible, that is a very small.
3:38
So, we have considered z1 is equal to z2.
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